n^2-26n+25=0

Solution for n^2-26n+25=0 equation:

n^2-26n+25=0

a = 1; b = -26; c = +25;
Δ = b2-4ac
Δ = -262-4·1·25
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-24}{2*1}=\frac{2}{2}
=1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+24}{2*1}=\frac{50}{2}
=25
$